below are systolic blood pressure measurements (mm Ho) taken from the right and
ID: 3361330 • Letter: B
Question
below are systolic blood pressure measurements (mm Ho) taken from the right and eft arms of a patient at random times during the day At a 10% significance level, do the data provide sufficient evidence to claim that there is a difference between the systolic blood pressure measurements of the right and left arms of the patient. NOTE: NO COMPUTATIONS ARE REQUIRED Right arm T1421145-11361131|130 (a) This problem is about (circle the correct one): One population mean Two population means, independent samples Two population means, paired samples One population standard deviation b) State the null and alternate hypotheses (c) What is the level of significance? st the assumptions and show the numbers or information given to meet each assumption The P-value = 0.4535 for the Shapiro-Wilk normality test. (e) Circle which of the following Statcrunch methods you would use to test the hypothesis stated in part (b). Z Stats-One sample T Stats- Two samples T Stats-Paired Sample Variance tests-One sample None of these since not all assumptions are met T Stats -One sample () If the P-value is 0.0044, show how you determine if Ho is rejected or not. g) Write the interpretation of the results of the hypothesis testExplanation / Answer
Solution:
We are given two sets of data.
X: Right arm
Y: Left arm
We have given X and Y values of one patient.
(a)Here we have to test two population means , paired sample.
(b) Null hypothesis: H0 : there is no difference between the systolic blood pressure measurements of the right arm and left arms f the patient.
Alternative hypothesis: Ha: there is difference between the systolic blood pressure measurements of the right arm and left arms f the patient.
(c) Level of significance: = 0.10
(d) We have to first check given data is normally distributed or not.
For this test we can use Shapiro Wilk normality test.
Assumptions:
The Shapiro-Wilk test is based on the correlation between the data and the corresponding normal scores.
In this test null hypothesis is H0: Data is normally distributed
Alternative hypothesis Ha: Data is not normally distributed.
Decision: Here if p-value < then we reject null hypothesis, otherwise fail to reject null hypothesis.
We are given P-value = 0.4536 which is greater than () 0.10
Hence we can say that data is normally distributed.
(e) For the above null hypothesis we have to use test, T stats-Paired sample.
(f) Here p-value = 0.0044 which < 0.10.
Hence we reject null hypothesis H0.
(g) Conclusion: There is sufficient evidence to say that there is difference between the systolic blood pressure measurements of the right arm and left arms f the patient.
Done
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.