1) Here are the read outs (area under the peak proportional to the amount of ami
ID: 33611 • Letter: 1
Question
1) Here are the read outs (area under the peak proportional to the amount of amino acid) for each amino acid from an amino acid analyzer. The first column contains the name of the amino acid followed by the second column labeled unk (unknown). This data was derived from 5 mg of a protein that was hydrolyzed in 6N HCl, dried, washed in water, dried again and resuspended in 1.0 ml of buffer and the entire sample was placed in the analyzer. The analyzer separated the amino acids, coupled them with ninhydrin and measured the amount of color to determine the relative amounts of each amino acid. The third column is the standard or known values of a mix of known amounts of each amino acid. For a standard amino acid mix a solution containing 1.7 mM each of the 20 amino acids was used and 0.58 mls of this standard mix were placed on the analyzer to give the values seen in column 3 (std). 1) From the residue weight of the amino acids determine the amino acid composition (number of amino acids) and the minimum molecular weight of the protein. (Hint best to set this up on an excel spread sheet).
Explanation / Answer
Based on the given data, the total analyzed protein concentration is 5 mg in 1 ml. in this method the protein sample was treated with the 6 molar HCl. So, due acid hydrolysis the tryptophan is destroyed. 1 mg of protein contains approximately
Each amino acid has residue molecular weight about 110 Daltons. 1 mg is equal to 602213665168000000000 Daltons, so 602213665168000000000/110 = 5.4746697e+18 amino acids for one mg. total 5 mg contains 2.7373348e+19 amino acids. Thus, minimum molecular weight of the protein is 3.0110683e+21Daltons.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.