The owner of a golf course wants to determine if his golf course is more difficu

Question

The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 25 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 25 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on his friend's course) is 1.78 and the standard deviation of the differences is 16.388. Calculate a 95% confidence interval to estimate the average difference in scores between the two courses.

1)

2)

3)

4)

5)

1)

(4.985, 8.545)

2)

(-4.97, 8.53)

3)

(-1.498, 5.058)

4)

(-0.284, 3.844)

5)

(-4.985, 8.545)

Explanation / Answer

The critical value at 95% interval is 2.064

Margin of error = (2.064*16.388)/5 = 6.765

95% Interval

(1.78-6.765, 1.78+6.765)

= (-4.985, 8.545)

So, Correct Option is E

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.