Help please!!!!!!! 1 7A/11.11 points | Previous Answers llowskyintroStati 7.Hw.0
ID: 3360470 • Letter: H
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Help please!!!!!!!
1 7A/11.11 points | Previous Answers llowskyintroStati 7.Hw.062. Suppose that the distance of fly balls hit to the outfield (in baseball) is normaly distributed with a mean of 256 feet and a standard deviation of 58 feet. We randomly sample 49 fly balls. Part (a) If R average distance in feet for 49 fly bals, then gve the distribution of R. Round your standard deviaton to two decimal places. 256 8.28 Part (b) Whet is the probebility that the 49 balls traveled an average of less than 248 1eet? (Round your answer to four decimal places.) Skotch tho graph. Scale the horizontal axa for Shade the regon oorresponding to to probablity. bl Part (c) Find the 80m percentle of the disribution of tne average of 49 fly bals. (Round your answer to two decimal places.)Explanation / Answer
Mean is 256 and s is 58, standard error for 49 balls is s/sqrt(N)=58/sqrt(49)=8.2857
b) P(xbar<248)=P(z<(248-256)/8.2857)=P(z<-0.96) or 1-P(z<0.96), from normal distribution table we get 1-0.8315=0.1685
correct curve is D
c) for 80% the z value can be found form the normal distribution table as 0.84
thus answer is mean+SE*z=256+0.84*0.1685=256.14154
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