**See below- I just need help with the 3rd part please. I\'ve included the answe
ID: 3360017 • Letter: #
Question
**See below- I just need help with the 3rd part please. I've included the answers given for parts 1 & 2.
Question: An experiment was performed to determine whether knowledge of the form of the embedded image affe...
An experiment was performed to determine whether knowledge of the form of the embedded image affected the time required for subjects to fuse the images. One group of subjects (group NV) received either no information or just verbal information about the shape of the embedded object. A secnd group (group VV) received both verbal information and visual information (e.g., a drawing of the object). GROUP N MEAN ST DEV ST ERROR NV 43 8.560 8.085 1.233 VV 35 5.551 4.802 0.812
1. Find the 95% confidence interval for (muNV - mu VV). (Use the fact that for the 95% CI, t*34 = 2.032, rather than closest value in Table D, i.e., t*30= 2.042 and carry calculations to 4 significant digits.)
2. Use the 95% confidence interval to test the null hypothesis visual information does not affect the time to fuse the images (muNV - muVV).
3. The confidence interval provides more information than whether or not the null of no difference is rejected. Give two other claims for (muNV - muVV), one that is rejected and one that is not rejected by these data.
Please Answer each question
Answer:
An experiment was performed to determine whether knowledge of the form of the embedded image affected the time required for subjects to fuse the images. One group of subjects (group NV) received either no information or just verbal information about the shape of the embedded object. A secnd group (group VV) received both verbal information and visual information (e.g., a drawing of the object). GROUP N MEAN ST DEV ST ERROR
NV 43 8.560 8.085 1.233
VV 35 5.551 4.802 0.812
1. Find the 95% confidence interval for (muNV - mu VV). (Use the fact that for the 95% CI, t*34 = 2.032, rather than closest value in Table D, i.e., t*30= 2.042 and carry calculations to 4 significant digits.)
=(0.0096, 6.0084)
2. Use the 95% confidence interval to test the null hypothesis visual information does not affect the time to fuse the images (muNV - muVV).
Since the 95% CI does not contain 0 value, the null hypothesis is rejected.
We conclude that visual information affect the time to fuse the images .
X-Y + tclar Va + |Explanation / Answer
3.The confidence interval is completely in the positive region. So, an hypothesis, that muVV is greater than muNV will be rejected, since in such case, muNV - muVV is negative and lies out side the 95% confidence interval.
Another hypothesis can be that the knowledge of the form of the embedded image reduces the time required for subjects to fuse the images by more than 10%. In this case, the average reduction as per the experiment is 8.56-5.551 = 3.009, which is about 35%. Hence this hypothesis would be accepted.
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