Each student in a class of 60was randomly assigned one line of a random number t

Question

Each student in a class of 60was randomly assigned one line of a random number table. Each student then counted the odd-numbered digits in a 38-digit line. The even digits are 0, 2, 4, 6 and 8. a. On average, in the list of 38 digits, how many odd-numbered digits would each student find? b. If each student found a 90% confidence interval for the percentage of odd-numbered digits in the entire random number table, how many intervals (out of 60) would you expect not to capture the population percentage of 50%? a. On average each student would find nothing odd-numbered digits.

Explanation / Answer

number of digits = 38

probability of odd digit = 0.5

a)

number of odd numbered digits = 38 * 0.5 = 19

b)

the expected number of intervals which captures the population percentage of 50%

= total number of intervals * b

= 60 * 90%

= 54

expecetd number of intervals which does not capture 50%

= 60% * 10%

= 6 ........ans

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