Question Help * Listed below are systolic blood pressure measurements (in mm Hg)

Question

Question Help * Listed below are systolic blood pressure measurements (in mm Hg) oblained from the same woman. Find the regression equation, letting the right arm blood pressure be the predictor (x) variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is 90 mm Hg Use a 005 91 Right Arm Left Arm 100 177 172 144147 147 The regression equation is y- (Round to one decimal place as needed ) Given that the systolic bi od pressure in the right arm s 90 mmHg the best pred cted s st c bi od press (Round to one decimal place as needed ) en he a mi S mm HB Enter your answer in each of the answer boxes.

Explanation / Answer

Here the regression equation calculation will require the following values. x, y, xy and x2

Where X = right arm values and y = left arm values

Here n = 5

so lets say line equation is y^ = a +bx

and a and b = line constants.

so by formulas

a = [(y) (x2 ) - (x) (xy)]/ [ n (x2 ) - (x)2 ]

all the values are given above and putting all these values from the table, we get

a = [787 * 40250 - 446 * 70764] / [5 * 40250 - 4462]

a = 116006/ 2334 = 49.70

b =  [ n(xy) - (x)((y)]/ [ n (x2 ) - (x)2 ]

b = [ 5 * 70764 - 446 * 787] / [5 * 40250 - 4462]

b = 2818/ 2334 = 1.2074

y^ = 49.70 + 1.2074x

Here x = 90 mm hg

y^= 49.70 + 1.2074 * 90 = 158.37 mm Hg

Right Arm (x) Left Arm (y) x^2 xy 100 177 10000 17700 99 172 9801 17028 91 144 8281 13104 78 147 6084 11466 78 147 6084 11466 sum 446 787 40250 70764

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