1. Twenty runners are in a cross - country race. Seven are from your home state.

Question

1. Twenty runners are in a cross - country race. Seven are from your home state. What is the probability that 3 runners from your home state finish 1st, 2nd, and 3rd? 24 .

2. From a group of 8 men and 9 women how many groups can be formed with 3 women and 2 men?

3.  In another series of random numbers: 5, 8, 19, 67, 43, 10, 9, 11, 1 If these numbers were an exhaustive list of outcomes and they had a uniform probability distribution which would you bet on?

4. Using the Standard Normal Distribution , What is the Cumulati ve area left of a z - score of .56 ? To the right?

5.

Explanation / Answer

1)
First 3 runners from the home state can be selected in 7C3 ways

Required probability = 7C3/20C3 = 35/1140 = 0.030701754

2)
3 women can be selected in 9C3 ways
2 men can be selected in 8C2 ways

Possible number of groups = 9C3 * 8C2 = 84*28 = 2352

3)
If these numbers follow uniform distribution, selecting any number would have same probability.

Hence any number can be selected for betting

4)
P(z < 0.56) = 0.712260281

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