1) 51 samples were analyzed, and the sample mean was 9.7 ounces. Can you determi
ID: 3358351 • Letter: 1
Question
1) 51 samples were analyzed, and the sample mean was 9.7 ounces. Can you determine the standard deviation of the sample?
D) 0.017
2) How do we interpret the p-value for this test?
There is only a 0.034% chance that this sample mean would be observed if the pharmacists are following regulations.
3) The pharmacist wants to create a 95% confidence interval to estimate the true average penicillin dosage being dispensed by her team. Fill in the pieces below:
t critical =
margin of error = (report to 3 decimal places)
low estimate = (report to 2 decimal places)
high estimate = (report to 2 decimal places)
4) What conclusion should the pharmacist reach about the volume of penicillin being dispersed by her team?
A) 0.500 10.2 ouncesExplanation / Answer
1)here std error of mean =(X-mean)/t =(9.7-10.2)/(-5.89)=0.0849
therefore std deviaiton =std error*(n)1/2 =0.0849*(51)1/2 =0.606
option C is correct
2)option D is correct
3) t critical =2.0086
margin of error =t*std error =0.171
lower estimate =sample mean -margin of errror =9.53
highestimate =sample mean +margin of errror =9.87
4)
C) The pharmacists are not dispersing the required amount of penicillin.Related Questions
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