A study compared three display panels used by air traffic controllers. Each disp
ID: 3357474 • Letter: A
Question
A study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel-emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the MINITAB output of a two-way ANOVA of the data.
Make pairwise comparisons of display panels A, B , and C by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Make pairwise comparisons of emergency conditions 1, 2, 3, and 4 by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Which display panel minimizes the time required to stabilize an emergency condition? Does your answer depend on the emergency condition? Why?
Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using display panel B. (Round your answers to 2 decimal places.)
References
eBook & Resources
A study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel-emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the MINITAB output of a two-way ANOVA of the data.
35 30 25 20 15 10 3 Panel A Panel B Panel CExplanation / Answer
Answer:
a)
Interpret the interaction plot in the above table. Then test for interaction with = .05.
Panel B requires (Click to select)less time to stabilize the emergency condition.
F(int)= .30, p-value= .923; (Click to select)cannot reject H0, no interaction exists.
(b)
Test the significance of display panel effects with = .05.
F = 25.92, p-value = .0000; (Click to select) reject H0
(c)
Test the significance of emergency condition effects with = .05.
F = 98.90, p-value = .0000; (Click to select)reject H0
(d)
Make pairwise comparisons of display panels A, B , and C by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Tukey Simultaneous Tests for Differences of Means
Difference
of Panel
Levels
Difference
of Means
SE of
Difference
Simultaneous
95% CI
T-Value
Adjusted
P-Value
B - A
-4.87
1.10
(-7.82, -1.93)
-4.42
0.002
C - A
3.00
1.10
(0.06, 5.94)
2.72
0.046
C - B
7.87
1.10
(4.93, 10.82)
7.13
0.000
Individual confidence level = 97.94%
Tukey q.05 = , MSE = 4.875
uA – uB:
[ , ]
uA – uC:
[ , ]
uB – uC:
[ , ]
(e)
Make pairwise comparisons of emergency conditions 1, 2, 3, and 4 by using Tukey simultaneous 95 percent confidence intervals. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.)
Tukey Simultaneous Tests for Differences of Means
Difference
of condition
Levels
Difference
of Means
SE of
Difference
Simultaneous
95% CI
T-Value
Adjusted
P-Value
2 - 1
7.67
1.27
(3.88, 11.45)
6.01
0.000
3 - 1
15.33
1.27
(11.55, 19.12)
12.03
0.000
4 - 1
-5.17
1.27
(-8.95, -1.38)
-4.05
0.008
3 - 2
7.67
1.27
(3.88, 11.45)
6.01
0.000
4 - 2
-12.83
1.27
(-16.62, -9.05)
-10.07
0.000
4 - 3
-20.50
1.27
(-24.29, -16.71)
-16.08
0.000
Individual confidence level = 98.83%
u1 – u2:
[ , ]
u1 – u3:
[ , ]
u1 – u4:
[ , ]
u2 – u3:
[ , ]
u2 – u4:
[ , ]
u3 – u4:
[ , ]
(f)
Which display panel minimizes the time required to stabilize an emergency condition? Does your answer depend on the emergency condition? Why?
(Click to select)Panel B minimizes the time required to stabilize an emergency condition.
(Click to select)No, there is (Click to select)no interaction.
(g)
Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using display panel B. (Round your answers to 2 decimal places.)
Confidence interval
[ 3.93, 12.07 ]
(8±2.101*1.935)
a)
Interpret the interaction plot in the above table. Then test for interaction with = .05.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.