Aes hummingbird weight or these birds SX-3 15 grans. Based on previous studies,

Question

Aes hummingbird weight or these birds SX-3 15 grans. Based on previous studies, we can assume that the weights of Allen's hunnin birds have a normal di tribution, with Suppose a small group nhats been studied by uthe 20 lens hummigards has been ider study in Ateena 40 grain. (a Find an 80% confidence interval for the average wights of Alen's hummingbirds-the study region lower mit upper limit margin of error oo8 Round your ara te two dedinal Part (b) what conditions are nacessary for your calolations? (Select al that apply) is large unform distribution of weghts 15 known normal distribution of weights (c) Give a brief interpretation of your results in the contaxt of this problem There is an 80% chance that the interval is one of the intervals containing the tu. average-eight of allen's hummingbird, n this region There is a 20% chance that the interval i, one of the intenais containing the tre orage neght of Allen's hummingbrds it this regan. The probability that this interva, contains the true everage neight of Mer's hummingbirds 40. The probability that this interval contains the true average weight or Aler's humningsins s20, The probablity to the true average weight of Alen's hunimingbirds is equal to the sampla men E- 5 i 6 fer the mean-eight, of tne tummingbirds. (Round up to the rarest (d) Find tne snple strs necessary for 80% confidence evel sith a m whole numbar) arimal error oferirnat. hummingbirds 2017-11-06 22:02

Explanation / Answer

a) here std error of mean =std deviation/(n)1/2 =0.4/(20)1/2 =0.0894

for 80% CI ;critical value z =1.2816

hence lower limit =sample mean -z*std error =3.04

upper limit =sample mean +z*std error =3.26

margin of error E =z*Std error =0.11

b)

normal distribution of weights

c)

there is an 80% chance that .................

d)

here margin of error data is not clear ; please reply so that I can answer

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