A genetic experiment involving peas yielded one samp e o offspring consisting o

Question

A genetic experiment involving peas yielded one samp e o offspring consisting o 443 green peas and 173 yellow peas Use a 0.05 significance level to test the claim that under the same circumstances, 26% o offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution What are the null and altemative hypotheses? A. Ho' p=026 H p> 026 C. Ho: p 0.26 OB, Ho, p=026 H p

Explanation / Answer

The statistical software output for this problem is:

One sample proportion summary hypothesis test:
p : Proportion of successes
H0 : p = 0.26
HA : p 0.26

Hypothesis test results:

Hence,

Null and Alternative Hypotheses: Option C is correct.

z = 1.18

P - value = 0.2382

Conclusion: Option A is correct.

Final conclusion: Option B is correct.

Proportion Count Total Sample Prop. Std. Err. Z-Stat P-value p 173 616 0.28084416 0.017673077 1.1794299 0.2382

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