study was conducted to compare the proportion of drivers in Boston and New York

Question

study was conducted to compare the proportion of drivers in Boston and New York who wore seat belts while driving. Data were oollected, and the proportion wearing seat belts in Boston was 0.581 and the proport on wearing seat belts in New York was 0.632. Dua to lacal laws at tha tima tha study was canducted, it was suspacted that a smaller proportion af drivars wear soat halts in Baston than Naw York. (4) Find the test statistic for this lest using Ha: Po pNY. (Use standard error = 0.101.) (b) Determine the p-value (c) Based on this p-value, which or the following would you expect for a 95% confidence interval for p' PNY? (3 decimal places) (3 decimal places) Some values in the interval are positive and some are negative. All values in the interval are negative. All values in the interval are positive. (d) What is the coect conclusion? O Tha propartian of Roston drivers wearing saat balts was significantly highar than tha praportion of New York drivers waaring saat halts The proportion of Boston drivers wearing seat belts was significantly lower than the proportion of New York drivers wearing seat belts. There was no significant difference between the proportion of drivers wearing seat belts in Boston and New York.

Explanation / Answer

a) Test statistic = (0.581-0.832)/0.101 = -2.485

b) p - Value = P(z < -2.485) = 0.007

c) All values in the interval are negative. Option B is correct.

d) Option B is correct.

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