The following is sample information. Test the hypothesis that the treatment mean

Question

The following is sample information. Test the hypothesis that the treatment means are equal. Use the 0.05 significance level. Treatment 1 Treatment 2 Treatment 3 7 2 3 8 3 5 9 4 6 9 3 4 (a) State the null hypothesis and the alternate hypothesis. H0; H1; (b) What is the decision rule? (Round your answer to 2 decimal places.) H0 if the test statistic is greater than. (c&d) Compute SST, SSE, and SS total and complete an ANOVA table. (Round SS, MS, and F values to 2 decimal places.) Source SS df MS F Treatments Error Total (e) State your decision regarding the null hypothesis. H0

Mainly only need section B answered correctly.

Explanation / Answer

H0: There is no difference between treatment means

Ha: There is a difference between treatment means

alpha:5%

b) Decision Rule

F critical value at (1,11) d.f with 5% level is 4.844

Hence F cal > 4.844, we reject the H0.

c) ANOVA TABLE

e) F cal=0.0135

F cal < F critical value, we do not reject the H0,

Hence claim is not significant

ANOVA Source of Variation SS df MS F P-value F crit Tretaments 0.089744 1 0.089744 0.013554 0.909417 4.844336 Error 72.83333 11 6.621212 Total 72.92308 12

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