To test the relationship between gender and ratings of a promiscuous partner, a

Question

To test the relationship between gender and ratings of a promiscuous partner, a group of men and women was given a vignette describing a person of the opposite sex who was in a dating relationship with one, two, or three partners. Participants rated how positively they felt about the individual described in the vignette, with higher ratings indicating more positive feelings.

(a) Complete the F-table and make a decision to retain or reject the null hypothesis for each hypothesis test. (Assume experimentwise alpha equal to 0.05.)

State the decision for the main effect of gender.

Retain the null hypothesis.Reject the null hypothesis.    

State the decision for the main effect of promiscuity.

Retain the null hypothesis.Reject the null hypothesis.    

State the decision for the interaction effect.

Retain the null hypothesis.Reject the null hypothesis.    

(b) Based on the results you obtained, what is the next step?Compute simple main effect tests for the significant interaction.No further analysis is needed, because none of the effects are significant.    Compute pairwise comparisons for the gender factor.Compute pairwise comparisons for the promiscuity factor.

Source of Variation SS df MS F Gender 5 Promiscuity Gender × Promiscuity 156 Error 570 114 Total 871

Explanation / Answer

There are two factors in gender, male and female. So, i=2

There are three factors in promiscuity, one, two or three. So, j=3

Critical value of F(1,114) at 5% level = 3.92

Calculated F for Gender, 1.00 < 3.92, the critical value.

Retain the null hypothesis.

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Critical value of F(2,114) at 5% level = 3.08

Calculated F for Promiscuity, 14.00 > 3.08, the critical value.

Reject the null hypothesis.

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Critical value of F(2,114) at 5% level = 3.08

Calculated F for Interaction, 15.60 > 3.08, the critical value.

Reject the null hypothesis.

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(b) Since null hypothesis of Promiscuity is rejected:

Compute pairwise comparisons for the promiscuity factor.

Source SS DF MS=SS/df F=MS/MS Error Gender 5 i-1=1 5/1=5 5/5=1.00 Promiscuity 871-(5+156+570)=140 j-1=2 140/2=70 70/5=14.00 Gender*Promiscuity 156 (i-1)(j-1)=2 156/2=78 78/5=15.60 Error 570 114 570/114=5 Total 871 1+2+2+114=119

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