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An experimenter randomly divided a group of volunteers into two groups. One grou

ID: 3355716 • Letter: A

Question

An experimenter randomly divided a group of volunteers into two groups. One group fasted for 24 hours and the other for 48 hours. One person in the 24-hour group dropped out of the study. Scores below represent the number of ounces of Yummi (Very Vanilla) consumed during the first 10 minutes after the fast. Perform a t test, calculate d, and write a sentence summary of your results.

Please submit all necessary calculations and circle/or place a box around your answers so that I can easily locate the scores.

Please show all necessary stepts prior to calculating the t.

Please state your conclusions in three paragraph format (4 points). Must address the following sections, including the p symbol.
1. reject or fail to reject statement
2. if there is or if there is no relationship
3. specifically stating the conclusion by eyeballing the means.

4. don’t forget to add the effect size statement after calculating the d.

24 hours 48 hours
26 18
35 24
23 16
30 17
14

Explanation / Answer

H0: D = 0

H1: D 0

24 hours

48 hours

Diff D

Di-D

(Di-D)^2

26

18

-8

-3

9

35

24

-11

-6

36

23

16

-7

-2

4

30

17

-13

-8

64

0

14

14

19

361

Average

Average

Average

Sum

28.5

17.8

-5

474

D=ED/n=-5

S.D=(E(Di-D)2/n-1)=474/4=10.8857705

tSTAT=D-µ /S.D/n

Where tSTAT has n - 1 d.f

tSTAT=-5-0/10.8857705/5

      =-1.02706

tCRIT is +/- 2.77. Hence cannot reject the null hypothesis. There is no difference between the scores of two groups

cohen’s d: -

28.5-17.8/10.8857705

10.7/10.8857705

0.9829 (this is a large effect size)

p-value is 0.362465.

24 hours

48 hours

Diff D

Di-D

(Di-D)^2

26

18

-8

-3

9

35

24

-11

-6

36

23

16

-7

-2

4

30

17

-13

-8

64

0

14

14

19

361

Average

Average

Average

Sum

28.5

17.8

-5

474

D=ED/n=-5

S.D=(E(Di-D)2/n-1)=474/4=10.8857705

tSTAT=D-µ /S.D/n

Where tSTAT has n - 1 d.f

tSTAT=-5-0/10.8857705/5

      =-1.02706

tCRIT is +/- 2.77. Hence cannot reject the null hypothesis. There is no difference between the scores of two groups

cohen’s d: -

28.5-17.8/10.8857705

10.7/10.8857705

0.9829 (this is a large effect size)

p-value is 0.362465.

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