Problem 3 (5 points) a. (1 point) Consider a class of 4 students, 2 boys and 2 g
ID: 3355280 • Letter: P
Question
Problem 3 (5 points) a. (1 point) Consider a class of 4 students, 2 boys and 2 girls. Suppose that these students will be grouped into two teams of equal size. Assuming that the teams are selected at random, determine the probability that there is one all-boy team and one all-girl team. Explain b. (1 point) Consider a class of 10 students, 5 boys and 5 girls. Suppose that these students will be grouped into two teams of equal size. Assuming that the teams are selected at random, determine the probability that there is one all-boy team and one all-girl team. Explain c. (1 point) Consider a class of 6 students, 4 boys and 2 girls. Suppose that these students will be grouped into three teams of equal size. Assuming that the teams are selected at random, determine the probability that there are two all-boy teams and one all-girl team. Explain d. (1 point) Consider a class of 15 students, 10 boys and 5 girls. Suppose that these students will be grouped into three teams of equal size. Assuming that the teams are selected at random, determine the probability that there are two al boy teams and one all-girl team. Explain e. (1 point) Consider a class of 20 students, 10 boys and 10 girls. Suppose that these students will be grouped into four teams of equal size. Assuming that the teams are selected at random, determine the probability that there are two all-boy teams and two all-girl teams. ExplainExplanation / Answer
No. of teams possible = 4!/ [2! *2!] /2 = 3 [ one person can have one of the three other partners, only one combination leads to all girls team.
Probability = 1/3
b) No. of ways = 10! /[5! * 5!]/2 = 126
Probability = 1/126
Please repost the other questions individually.
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