Suppose a movie starts at 5:00 p.m. and Lindsay, a customer who is always late,

Question

Suppose a movie starts at 5:00 p.m. and Lindsay, a customer who is always late, arrives at the movie theater at a random time between 5:10 p.m. and 5:55 p.m. Lindsay's late arrival time, in minutes, represented by X, models a uniform distribution between 10 and 55 min. Determine the height of the uniform density curve. Provide your answer with precision to three decimal places. height = Calculate the probability that Lindsay is late by 30 min or less, P(X 5 30). Provide your answer with precision to three decimal places P(X 30) =

Explanation / Answer

Height = (10+55)/2

= 32.5

So, height is 32.5

b)

P(X<=30)

= (30-10)/(55-10)

= 20/45

= 0.444

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