For question 12 and 13: The Gallup organization is interested in whether the Aff

Question

For question 12 and 13: The Gallup organization is interested in whether the Affordable Care Act's ("Obamacare's") support may be changing. In August, Gallup reported that among registered voters in the United States, 41% approved, 49% disapproved, and 11% had no opinion (the percents do not add to 100% due to rounding error). In October, Gallup surveyed 1528 registered voters: 679 approved, 762 disapproved, and 87 had no opinion. Is there evidence that voters' opinions have changed between August and October? 12. What is the appropriate test statistic to test the null hypothesis- opinions have NOTchanged between August and October? a) 1-43.75 b)x'=43.75 c) 0.027 d) 2=0.027 13. What is the appropriate critical value for the hypothesis test above at 95% confidence? a) 5.991 b) 7.378 c) 7.815 d) 9.348none of these For questions 14-18, consider the table below with opinions about the Affordable Care Act broken down by age categories 30 to 49 92 94 12 200 50 to 64 72 94 65+ 29 40 Total 269 294 35 600 18 to 29 Approve Disapprove66 No Opinion 8 Total 76 150 75 14. How many 18-29 year-olds in this survey would be expected to disapprove of the Affordable Care Act if age and opinion were independent? a) (66150)*(66294)-0.098 b) (150/600) *(294/600)*600 73.5 c) 66 d) (66/150)*(66/294)*600-59.27 e) None of the above 15. Can we use our chi-squared test for this data? a) No, because we expect a value of at least five in each box. b) No, because we expect a value of less than five in some boxes c) Yes, because we expect a value of at least 5 in each box d) Yes, because we expect a value of less than five in some boxes. 16. Assuming we can use the chi-squared distribution for this test, how many degrees of freedom would we have? a) 3b)4 c) 6 d)12 e) none of these

Explanation / Answer

(14) Expected Value = Row total * column Total / N.

Therefore age group 18 - 29 who would disapprove = (150 * 294)/600 = 73.5 (Option b).

(15) (Option c). Yes, because we expect a value of at least 5 in each box.

(16) Degrees of freedom = (Row - 1) * (Columns - 1) = (4 - 1) ( 3 - 1) = 3 * 2 = 6 (Option c).

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