The local ice cream shop keeps track of how much ice cream they sell versus the

Question

The local ice cream shop keeps track of how much ice cream they sell versus the temperature on that day. Here are their figures for the last 12 days: Ice Cream Sales us Temperature Temperature °C Ice Cream Sales 14.2 16.4 11.9° 15.2 18.5 22.1 19.4 25.1 23.4° 18.1 22.6 17.2 $215 $325 $185 $332 $406 $522 $412 $614 $544 $421 $445 $408 Determine the equation for the regression line: y - Determine the correlation coefficient: Use the equation to predict the sales when it's 20° C: Use the equation to predict the temperature when the sales are $150: x (round to 4 decimal places when necessary) (use 4 decimals if there are more than 4)

Explanation / Answer

The statistical software output for this problem is:

Simple linear regression results:
Dependent Variable: Ice Cream Sales
Independent Variable: Temperature
Ice Cream Sales = -159.47415 + 30.087862 Temperature
Sample size: 12
R (correlation coefficient) = 0.95750662
R-sq = 0.91681893
Estimate of error standard deviation: 38.126501

Parameter estimates:

Analysis of variance table for regression model:

Hence,

Equation of regression line: y = -159.4742 + 30.0879 x

Correlation coefficient = 0.9575

When x = 20: y = -159.4742 + 30.0879 (20) = 442.2838

When y = 150: x = 10.2857

Parameter Estimate Std. Err. Alternative DF T-Stat P-value Intercept -159.47415 54.640728 0 10 -2.9185949 0.0153 Slope 30.087862 2.8659049 0 10 10.498555 <0.0001

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.