The following screen shot is the data on the Amazon stock prices from August 8,
ID: 3353314 • Letter: T
Question
The following screen shot is the data on the Amazon stock prices from August 8, 2016 through August 19, 2016. Use the data below to answer the questions Daily prices Date Aug 19, 2016 Aug 18, 2016 Aug 17, 2016 Aug 16, 2016 Aug 15, 2016 Aug 12, 2016 Aug 11, 2016 Aug 10, 2016 Aug 9, 2016 Aug 8, 2016 Aug 24, 2015 -Aug 22,2016 Update Volume 2,343,237 1,458,834 1,891,116 1,604,561 2,118,521 1,563,318 2,019,740 1,604,280 1,876,091 1,986,272 Close Open 761.90 762.49756.89 757.31 764.00 765.17 760.60 764.46 764.41 765.22 759.20 764.63 768.62 768.73 763.82 764.04 771.90 772.04 767.71 768.49 768.46 773.15 768.42 772.56 769.94773.75769.12 771.24 769.80 772.10 766.19 768.56 767.39 772.60 766.90 768.3 766.81767.00761.02 766.56 High Low 1. What is the mean of the close prices? Round your answer to two digits past the decimal 2. What is the variance of the close prices? State your answer without rounding. 3. What is the standard deviation of the close prices? Round your answer to two digits past the decimal. 4. What is the interval of values that is within one standard deviation of the mean of the close prices? Calculate the lower bound or left side of this interval by subtracting the standard deviation from the mean. Calculate the upper bound or right side of this interval by adding the standard deviation to the mean. 5. What is the interval of values that is within two standard deviations of the mean of the close prices? Calculate the lower bound or left side of this interval by subtracting two times the standard deviation from the mean. Calculate the upper bound or right side of this interval by adding two times the standard deviation to the mean.Explanation / Answer
Solution:
1)Mean of the close price=766.62
2)Variance of the close price=18.74514
3)Standard deviation of the close price=4.32
4)Interval values of close price within one standard deviation=(762.2864,770.9456)
5)Interval values of close price within two standard deviation=(757.9569,775.2751)
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