Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

> www.webassign.net/web/student/Assignment-Responses/submit?dep 18085921#011 IQR

ID: 3352445 • Letter: #

Question

> www.webassign.net/web/student/Assignment-Responses/submit?dep 18085921#011 IQR 245 troStatl 2 HW 110.general 10. Following are the published weights (in pounds) of all of the team members of Football Team A from a previous year. 177; 202; 212; 212; 232; 205; 185; 185; 178; 210; 206; 212; 184; 174 185; 242; 188; 212; 215; 247; 241; 223; 220; 260; 245; 259; 278; 270 280; 295; 275; 285; 290; 272; 273; 280; 285; 286; 200; 215; 185; 230; 250; 241; 190; 260; 250; 302; 265; 290; 276; 228; 265 Organize the data from smalest to largest value. Part (a) Find the median. Part (b) Find the first quartile. (Round your answer to one decimal place.) 205.5 Part (c) ace Rm

Explanation / Answer

e)

Q1= 206

Q3= 272

Q3-Q1= Middle 50% weights= They lie between 206 and 272

f)

We are talking about players in Team A and that is only a sample of the total population of football players

So, your answer would be (c)

g)

Here the sample and population are the same as we are only talking about all players in Team A

So, your answer would be (c)

h)

Population Mean= Average of all observations= 236.35

Population Standard Deviation= 37.49

236.36-3*37.49= 123

Below 3 SD from mean, the observation will be 123

236.36-x*37.49 = 216

x= (236.36-216)/37.49= 0.54

It is 0.54 SD away from mean

Below the mean to be precise

i)

Player B is 0.69 SD away from their team's mean weight

However, Player A is 0.54 SD away from his team's mean weight

Player A is heavier as per their team's stats

So, answer will be option- (b)

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote