Please come up with a word problem using the example below as a guide. Use the s
ID: 3352106 • Letter: P
Question
Please come up with a word problem using the example below as a guide. Use the same college example just different numbers please.
A sample of 36 students Irving College produce a mean gpa of 3.2. The standard deviation of all students is .6. Find the 95% confidence interval.
STEP 1: Find the standard deviation of the sample: .6 divided by square root of 36 = .1
STEP 2: Find the Z-score associated with 95% confidence (Go to table IV in the front of your book and find the Z-score that has .975 to the left of it. (We look for .975, because the table gives the area to the left of the Z-score [see the image at the top of the table], and if a Z-score has .975 to the left of it, it has .025 in the right tail. A confidence interval has "two tails", so the total in the tails is .025 + .025 = .05. The "inside" would be 1 - .05 = .95. The z-score is 1.96
HINT:
You can use the following numbers as guidelines for Z-scores:
Confidence Interval
Z-Score
99%
2.57
98%
2.33
95%
1.96
90%
1.65
STEP 3: Multiply the z-score and the standard deviation of the sample together: 1.96 * .1 = .196
STEP 4: Construct your confidence interval by subtracting this number from the mean (3.2-.196 = 3.04) and adding this number to the mean (3.2 +.196 = 3.396). The 95% confidence interval is 3.04 to 3.396.
Confidence Interval
Z-Score
99%
2.57
98%
2.33
95%
1.96
90%
1.65
Explanation / Answer
Ok. Here' the answer to your question. in case you have doubts please write back to me:
A sample of 64 students Irving College produce a mean gpa of 4.0. The standard deviation of all students is .4. Find the 99% confidence interval.
STEP 1: Find the standard deviation of the sample: .4 divided by square root of 64 = .05
STEP 2: Find the Z-score associated with 99% confidence (Go to table IV in the front of your book and find the Z-score that has .995 to the left of it. (We look for .995, because the table gives the area to the left of the Z-score [see the image at the top of the table], and if a Z-score has .995 to the left of it, it has .005 in the right tail. A confidence interval has "two tails", so the total in the tails is .005 + .005 = .01. The "inside" would be 1 - .01 = .99. The z-score is 2.57
STEP 3: Multiply the z-score and the standard deviation of the sample together: 2.57 * .1 = .257
STEP 4: Construct your confidence interval by subtracting this number from the mean (4.0-.257 = 3.743) and adding this number to the mean (4.0 +.257 = 4.257). The 99% confidence interval is 3.743 to 4.257).
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