the answer is not .65 and 5.75 Problem 2-21 Suppose that the average waiting tim

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the answer is not .65 and 5.75

Problem 2-21 Suppose that the average waiting time for a patient at a physician's office is just over 29 minutes. In order to address the issue of long patient wait times, some physicians' offices are using wait- tracking systems to notify patients of expected wait times. Patients can adjust their arrival times based on this information and spend less time in waiting rooms. The following data show wait times (minutes) for a sample of patients at offices that do not have a wait-tracking system and wait times for a sample of patients at offices with a wait-tracking system. With Wait-Tracking System 12 Without Wait Tracking System 65 10 34 23 47 15 12 25 32 31 32 17 (a) Considering only offices without a wait-tracking system, what is the z-score for the 10th patient in the sample (wait time 32 minutes)? If required, round your intermediate calculations and final answer to two decimal places. score (b) Considering only offices with a wait-tracking system, what is the z-score for the 6th patient in the sample (wait time 32 minutes)? If required, round your intermediate calculations and final answer to two decimal places. score

Explanation / Answer

(a)

Standard deviation of the sample waiting times for offices without a wait-tracking system = 16.99183

Mean = 29

x = 32

z - score = (32 - 29) / 16.99183 = 0.18

(b)

Standard deviation of the sample waiting times for offices with a wait-tracking system = 9.345231

Mean = 29

x = 32

z - score = (32 - 29) / 9.345231 = 0.32

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