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O.02sp) A container has 5 blue marbles, 3 red marbles, and 6 white marbles. If 3

ID: 3350833 • Letter: O

Question

O.02sp) A container has 5 blue marbles, 3 red marbles, and 6 white marbles. If 3 marbles are drawn with replacement, what is the probability that all three will be blue? 3. rea olwhrle A poll states that 35% of the workers in a large company have new computers. If 4 workers are selected at random, what is the probability that at least one worker has a new computer? 4, In a shipment of 30 televisions, 3 are defective. If 2 TV sets are randomly selected and tested without replacement, what is the probability that both are defective? 5.

Explanation / Answer

3)

Total marbles in the container = 5 + 3 + 6 = 14

P( Blue marble) = n( Blue marbles) / n( Total marbles) = 5 / 14

P( All three marbles are blue) = 5/14 * 5/14 * 5/14

= 0.0456

4)

X ~ Binomial(n,p) = Binomial(4 , 0.35)

Where n = 4 and p = 0.35

Binomial probability distribution is

P(X) = nCx px (1-p)n-x

P( X >= 1) = 1 - P( X = 0)

= 1 - 4C0 0.350 0.654

= 1 - 0.1785

= 0.8215

3)

P( Defective item) = 3 / 30

P( First defective item) = 3/30

Since second item drawn without replacement, there are 29 total TV sets are remaining with 2 defective.

P( Second defective item) = 2 / 29

P( Both defective items) = 3 / 30 * 2 / 29

= 0.0069