all Verizon 5:11 PM 0.64 points MinroStats 12.E 508.XP My Notes Ask Your Differe
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all Verizon 5:11 PM 0.64 points MinroStats 12.E 508.XP My Notes Ask Your Different varieties of the tropical flower Heiconia are fertilized by different species of hummingbirds. Over time, the lengths of the flowers and the form of the hummingbirds" beaks have evolved to match each other. Here are data on the lengths in millimeters of three varieties of these flowers on the island of Dominica. data429.dat Do a complete analysis that includes description of the data and a significance test to compare the mean lengths of the flowers for the three species. (Round your answers for x to four decimal places, s to three decimal places, and 5to three decimal places. Round your test statistic to two decimal places. Round your P-value to three decimal places. flower type bihai caribaea yellow eBook -0.04 points MntroSM9 t2E 511 My Notes Ask Your Iron-deficiency anemia is the most common form of malnutrition in developing countries, affecting about 50% of children and women and 25% of men. Iron pots for cooking foods had traditionally been used in many of these countries, but they have been largely replaced by aluminum pots, which are cheaper and lighter, Some research has suggested that food cooked in iron pots will contain more iron than food cooked in other types of pots. One study designed to investigate this issue compared the iron content of some Ethiopian foods cooked in aluminum-clay, and iron pots. One of the foods was yesiga wet, beef cut into small pieces and prepared with several Ethiopian spices. The iron content of four samples of yesiga wet cooked in each of the three types of pots is given below. The units are milligrams of iron per 100 grams of cooked food. data224.dat (a) Make a table giving the sample size, mean, and standard deviation for each type of pot. Is it reasonable to pool the variances? Note that with the small sample sizes in this experiment, we expect a large amount of variability in the sample of pot (b) Run the analysis of variance. Report the F statistic with its degrees of freedom and P-value. What do you conclude? (Round your test statistic to two decimal places. Round your P-value to three decimal places.) Conclusion: There is--Seoc level. atistically significant difference between the three treatment means at the = .05 eBook 11. 0.64 points Mhtestat9 13.E 5183P * My Notes Ask Your
Explanation / Answer
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MTB > AOVOneway 'Bihai'-'Yellow'.
One-way ANOVA: Bihai, Red, Yellow
Source DF SS MS F P
Factor 2 1237.40 618.70 473.38 0.000
Error 51 66.66 1.31
Total 53 1304.06
S = 1.143 R-Sq = 94.89% R-Sq(adj) = 94.69%
Level N Mean StDev
Bihai 16 48.230 0.854
Red 23 39.763 1.394
Yellow 15 36.041 0.962
Pooled StDev = 1.143
F = 473.38
P = 0.00
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ANOVA
MTB > AOVOneway 'Aluminum'-'Iron'.
One-way ANOVA: Aluminum, Clay, Iron
Source DF SS MS F P
Factor 2 16.156 8.078 40.11 0.000
Error 9 1.812 0.201
Total 11 17.969
S = 0.4488 R-Sq = 89.91% R-Sq(adj) = 87.67%
Level N Mean StDev
Aluminum 4 1.8025 0.3396
Clay 4 4.3275 0.5846
Iron 4 1.9350 0.3834
Pooled StDev = 0.4488
F = 40.11
P = 0.00
Conclusion: There is no statistically significant difference between the three treatment means at 5% level.
Bihai Red Yellow 48.04 39.4 37.12 47.13 41.13 36.5 49.03 40.84 36.23 48.69 39.27 37.52 48.39 39.56 37.18 48.33 39.91 35.83 49 38.75 35.85 47.5 38.76 35.45 48.87 40.14 35.42 47.27 37.43 34.58 48.51 40.12 36.01 48.05 40.84 34.81 49.12 38.66 36.85 49.77 39.58 34.49 46.93 40.44 36.77 47.05 37.07 39.31 41.16 38.71 43.89 39.12 40.6 39.87Related Questions
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