Help with Antiderivative A particle is moving with the given data. Find the posi

Question

Help with Antiderivative

A particle is moving with the given data. Find the position of the particle. v(t) =1.5 root, s(9) =35 s(t) = A stone is dropped from the upper observation deck of a tower, 100 m above the ground. (Assume g = 9.8 m/s2.) Find the distance (in meters) of the stone above ground level at time t h{t) = How long does it take the stone to reach the ground? (Round your answer to two decimal places.) With what velocity does it strike the ground? (Round your answer to one decimal place.) If the stone is thrown downward with a speed of 9 m/s, how long does it take to reach the ground? (Round your answer to two decimal places.)

Explanation / Answer

7)s=1.5(t^1.5)/1.5 +c

==>35=27+c

==>c=8

s=1.5(t^1.5)/1.5 +8

8)a)=4.9t^2

b)t=4.52sec

c)v=44.27m/s

d)100=9t+4.9t^2

==>t=3.7sec

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