Not sure how to do this. Find the limit , where = e2t - 1/t; 4t/t3 + 5t; ln(t +

Question

Not sure how to do this.

Find the limit , where = e2t - 1/t; 4t/t3 + 5t; ln(t + 1) Find the limit , where = 100/5 + e-t; 4t2/2t2 - t + 1; te-t

Explanation / Answer

1) lim t-->0 r(t) = 0 (e^2t - 1)/t, lim t-->0 4t/(t^3+5t), lim t-->0ln(t+1)> = 0 (e^2t - 1)/t, lim t-->0 4t/(t*(t^2+5)), ln(0+1)> = 0 (e^2t - 1)/t, lim t-->0 4/((t^2+5)), 0 > = 0 (e^2t - 1)/t, 4/((0+5)), 0 > = 0 (e^2t - 1)/t, 4/5, 0 > apply L'Hospital's rule we get = 0 (2e^2t - 0)/1, 4/5, 0 > = 2) lim t-->0 r(t) = 0 100/(5+e^-t), lim t-->0 4t^2/(2t^2 - t+1 ), lim t-->0 te^-t> =

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