**********ONLY COMPLETE PARTS G-N*************** A melting point test of n=10 sa

Question

**********ONLY COMPLETE PARTS G-N***************

A melting point test of n=10 samples of a binder usedin manufacturing a rocket propellant resulted in xbar=154.2 degrees F. Assume that the melting point is normally distrubted with standard deviation = 1.5 degrees F a) Check the assumptions necessary to test H0:4-155 vs. Ha: 155 at the 1% significance level. [If you don't know if an assumption is satisfied based on the information provided, then state "We must assume b) Calculate the test statistic. c) Find the p-value. d) Make a decision. e) State the conclusion in terms of the problem. f Construct a confidence interval (CI) to test the hypotheses. Make a decision based on the CI. Does your decision match the decision in (d)? g) Describe a type I error in terms of the problem. What is the consequence of making a type I error? Suppose the binder would not be used if there's enough evidence for Ho' 155 because it would be deemed unsafe Describe a type ll error in terms of the problem What is the consequence of making a type Il error? Suppose the binder would be used if there's not enough evidence for Haji 155 because it is thought to be safe h) i) i) k) Which error could have been made here? I) What is the probability of making a type Il error, if the true mean is 153°F? m) What is the power of the test, if the true mean is 153°F? n) Suppose now that the true mean is 150°F. Without doing the calculation, would the power of the test be larger or smaller than the answer in the previous part?

Explanation / Answer

We are allowed to do 4 subparts question at a time. Post again for more subparts of question.

g) In statistical hypothesis testing, a type I error is the incorrect rejection of a true null hypothesis (also known as a "false positive" finding), while a type II error is incorrectly retaining a false null hypothesis (also known as a "false negative" finding).

Here, type 1 error would be to reject null when it is true. So, melting point is less than equal to 155, but we take it as greater than 155.

h) In type 1 case, we will not acccept null when it is true. Thus, melting point =155 but we wont use binder as we have made an error that melting point 155

i) Here, type 2 error would be to accept null when it is false. So, melting point is not equal to 155, but we take it as equal to 155.

i) In type 2 case, we will acccept null when it is not true. Thus, mmelting point is not equal to 155, but we take it as equal to 155. Thus, we will use binder and make an error. This wont be safe as we have made an error.

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.