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Green Box: Answer must be typed to four decimals. Purple Box: Answer must be cho

ID: 3340229 • Letter: G

Question

Green Box: Answer must be typed to four decimals.
Purple Box: Answer must be chosen from drop down menu.
Blue Box: Answer must be typed to either 2 or 3 decimals depending on whether the Z of t table is appropriate.

If possible, I would like to see the steps and formulas used to solve this problem. I posted this question earlier but I am not 100% satisfied with the answer.

The selling prices (in $) for the deluxe and standard model Ryobi wood sanders are shown for a sample of eight retail stores. Does the data suggest the difference in average selling price of these Ryobi models is more tharn $10 at =0.01? (See exercise 27 on page 458 of your textbook for a similar problem.) Retail Store Deluxe Standard 41 ALI 41 29 30 28 20 34 38 38 39 28 25 28 For the hypothesis stated above (in terms of Deluxe Standard) Question 1 What is the test statistic? Question 2 What is the conclusion? Deluxe-uStandard Question 3What is the p-value? Fill in only one of the following statements. f the Z table is appropriate,p-value If the t table is appropriate, p-value

Explanation / Answer

Given that,
mean(x)=38
standard deviation , s.d1=3.0237
number(n1)=8
y(mean)=26.25
standard deviation, s.d2 =3.5757
number(n2)=8
null, Ho: u1 = u2
alternate, H1: u1 > u2
level of significance, = 0.01
from standard normal table,right tailed t /2 =2.998
since our test is right-tailed
reject Ho, if to > 2.998
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =38-26.25/sqrt((9.14276/8)+(12.78563/8))
to =7.0971
| to | =7.0971
critical value
the value of |t | with min (n1-1, n2-1) i.e 7 d.f is 2.998
we got |to| = 7.09708 & | t | = 2.998
make decision
hence value of | to | > | t | and here we reject Ho
p-value:right tail - Ha : ( p > 7.0971 ) = 0.0001
hence value of p0.01 > 0.0001,here we reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 > u2
test statistic: 7.0971
critical value: 2.998
decision: reject Ho
p-value: 0.0001
we have enough evidence to support the claim