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ID: 3339736 • Letter: O

Question

on S SASO Demand for S SAS.Logo M S SAS. Logo Man. ) Save a Report SA con _a T ke Test nNA × M bo (934) no bladboardcom assessment id 159753 1&course; id 63210 18content.ild- 4588594 18step-nul TION 10 A clinical trial is run to assess the effects of different forms of regular exercise on HDL levels in persons between the ages of 18 and 29 Participants in the study are randomly assigned to one of three exercise groups-Weight training, Aerobic exercise or Stretching/Yoga-and instructed to follow the program for 8 weeks. Their HDL levels are measured after 8 weeks and are summarized below Exercee Group Mean Weight Traning 49.7 Aerobic E 20 20 57 0 We want to test the null hypothesis that the mean HDL levels in each of the exercise groups are equal, vs. the alternative hypothesis that the means are nol all equal, at alpha 0.05. What is the appropriate test statistic? O 1 Krankal Walis tost O2 ANOVA O3Che square test of rdeprdence O 5 Independent sampies t-test

Explanation / Answer

10) ANOVA should be used.

Analysis of Variance (ANOVA) is a statistical method used to test differences between two or more means. It may seem odd that the technique is called "Analysis of Variance" rather than "Analysis of Means." As you will see, the name is appropriate because inferences about means are made by analyzing variance.

Critical value = 3.16

F = 0.378

Accept null