Tyler and Aziz are playing a friendly game of Blackjack. Aziz is the dealer and

Question

Tyler and Aziz are playing a friendly game of Blackjack. Aziz is the dealer and has chosen to use two decks of cards. Aziz reveals one of his cards to be a Jack (NB: King, Queens and Jacks are all worth 10 points). Tyler receives a Queen and a 10, giving him a combined score of 20, so he chooses to stay (ie. not draw any more cards). Given Tyler's hand, what is the probability that Aziz's other card is an Ace (NB: Aces are worth either 1 or 11 points), ie. the probability of Aziz getting 21 and beating Tyler without having to draw any more cards? 2. [8 marks]

Explanation / Answer

They are using two decks

So, a total of 104 cards, of which 3 are already drawn. So remaining 101 cards

Of which 8 are aces

So, given the current situation the probability of ace is P(Ace ) = 8/101

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