A study that looked at beverage consumption used sample sizes that were much sma

Question

A study that looked at beverage consumption used sample sizes that were much smaller than previous national surveys. One part of this study compared 20 children who were 7 to 10 years old with 5 who were 11 to 13. The younger children consumed an average of 8.2 oz of sweetened drinks per day while the older ones averaged 14.3 oz. The standard deviations were 10.9 oz and 8.2 oz respectively. Solve for missing values.

(c) Give a 95% confidence interval for the difference in means. (Round your answers to four decimal places.)

(?,?)

Explanation / Answer

her they have used conservative method for which degree of freedom =minimum(n1,n2)-1 =min(20,5)-1 =4

Here they have not specified if it is one tailed or two tailed test:

for 4 degree of freedom and one tailed test p value =0.1191

and for 4 degree of freedom with twoitailed test p value =0.2383

c)

here sample mean difference =8.2-14.3=-6.1

for 4 degree of freedom and 95% CI ; critical value of t =2.7764

hence  95% confidence interval for the difference in means =sample mean difference -/+ t*SED

=-18.3247 to 6.1247

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