An Urn contains two white marbles and one black marble. A marble is drawn from t

Question

An Urn contains two white marbles and one black marble. A marble is drawn from the Urn without replacement and put aside without my seeing it. Then a second marble is drawn, and it is white.

What is the probability that the unknown removed marble is white, and what is the probability that it is black?

0 the first marble is white the second marble is white) p(the first marble is black | the second marble is white) p(the first marble is white ! the second marble is white) p(the first marble is black | the second marble is white) = 0.333 p (the first marble is white |the second marble is white)- .5 plthe first marble is black | the second marble is white) .5 p(the first marble is white p(the first marble is black | the second marble is white) 0.3333 0.6667 O 0.6667 O the second marble is white) 1.0 0.0

Explanation / Answer

answer is first one i.e.

P(first marbel is white given that second marble is whit) = (2/3)*(1/2) = 0.3333

P(first marbel is black given that second marble is whit) = (1/3)*(1/2) = 0.6667

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