his Question: 1 pt 20 of 20 (19c Find the equation of the regression line for th
ID: 3337003 • Letter: H
Question
his Question: 1 pt 20 of 20 (19c Find the equation of the regression line for the given data Then construct a scatter plot of the data and draw the regression line (The pair of vanablies have a sant correlation.) Then use the regression equation to predict the value of y for each of the given x-values, if meaningul The number of hours 6 students spent for est tours spent studying est score, y 1 35 43 2 52 (a) x = 2 hours (c)x-14 hours (B) x=25hours d) x-3 5 hours 2 51 61 70 to two O A. B. oc. WhExplanation / Answer
calculation procedure for regression
mean of X = X / n = 3.1667
mean of Y = Y / n = 52
(Xi - Mean)^2 = 14.833
(Yi - Mean)^2 = 776
(Xi-Mean)*(Yi-Mean) = 96
b1 = (Xi-Mean)*(Yi-Mean) / (Xi - Mean)^2
= 96 / 14.833
= 6.472
bo = Y / n - b1 * X / n
bo = 52 - 6.472*3.1667 = 31.505
value of regression equation is, Y = bo + b1 X
Y'=31.505+6.472* X
a.
when x = 2 hours then
Y' = 31.505+6.472* 2 = 44.449
Y' = 44.44
b.
when x = 2.5 hours then
Y' = 31.505+6.472* 2.5 = 47.685
Y' = 47.68
c.
when x = 14 hours then
Y' = 31.505+6.472* 14 = 122.113
Y' = 122.11
d.
when x = 3.5 hours then
Y' = 31.505+6.472* 3.5 = 54.157
Y' =54.15
graph below shown is option B
Line of Regression Y on X i.e Y = bo + b1 X X Y (Xi - Mean)^2 (Yi - Mean)^2 (Xi-Mean)*(Yi-Mean) 1 35 4.695 289 36.834 2 43 1.361 81 10.5 2 52 1.361 0 0 4 51 0.694 1 -0.833 5 61 3.361 81 16.5 5 70 3.361 324 32.999Related Questions
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