assume that womens heights are normally distributed with a mean given by u= 62.4

Question

assume that womens heights are normally distributed with a mean given by u= 62.4 in. and a standard deviation given by o= 2.2 in. if 10 women are randomly selected, find the probability that they have a mean height between 62.2 in and 63.2 in. assume that womens heights are normally distributed with a mean given by u= 62.4 in. and a standard deviation given by o= 2.2 in. if 10 women are randomly selected, find the probability that they have a mean height between 62.2 in and 63.2 in. assume that womens heights are normally distributed with a mean given by u= 62.4 in. and a standard deviation given by o= 2.2 in. if 10 women are randomly selected, find the probability that they have a mean height between 62.2 in and 63.2 in.

Explanation / Answer

given mean =62.4

std =2.2

n= 10

we have formulea

z = x^-mu /( std /sqrt n)

z1 = (62.2-62.4)/(2.2/sqrt 10) =-0.287   from standard z table we have 0.3897

z2= (63.2-62.4)/(2.2/sqrt 10)= 1.149 from standard z table we have 0.8729

find the probability that they have a mean height between 62.2 in and 63.2 in.

p(z1<z>z2)= 0.8729-0.3897= 0.4832

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