In the carnival game Under-or-Over-Seven, a pair of fair dice is rolled once, an

Question

In the carnival game Under-or-Over-Seven, a pair of fair dice is rolled once, and the resulting sum determines whether the player wins or loses his or her bet. For example, using method one, the player can bet $2.00 that the sum will be under 7, that is, 2, 3, 4, 5, or 6. For this bet, the player wins $2.00 if the result is under 7 and loses $2.00 if the outcome equals or is greater than 7. Similarly, using method two, the player can bet $2.00 that the sum will be over 7, that is, 8, 9, 10, 11, or 12. Here, the player wins $2.00 if the result is over 7 but loses $2.00 if the result is 7 or under. A third method of play is to bet $2.00 on the outcome 7. For this bet, the player wins S8.00 if the result of the roll is 7 and loses $2.00 otherwise. Complete parts (a) through (d) Click the icon to view a table of all possible outcomes of a two dice roll 7 12 -$ 2 Data Table (Type an exact answer in simplified form.) b. Construct the probability distribution representing the different outcomes that are possible for a $2.00 bet using method two. Outcomes of a two dice roll 1 23 4 5 6 S2 12 7 -S 2 (Type an exact answer in simplified form.) 456789 10 5 678 9 10 11 6 789 10 11 12 c. Construct the probability distribution representing the different outcomes that are possible for a $2.00 bet using method three. P(X) (Type an exact answer in simplified form.) Print Done

Explanation / Answer

c)

x P(x)

$8 6/36 = 1/6

-$2 1 - 6/36 = 5/6

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.