In a survey of 10951095 adults, a poll asked, \"Are you worried or not worried a

Question

In a survey of 10951095 adults, a poll asked, "Are you worried or not worried about having enough money for retirement?" Of the 1095 surveyed, 650 stated that they were worried about having enough money for retirement. Construct a 99% confidence interval for the proportion of adults who are worried about having enough money for retirement. A 99% confidence interval for the proportion of adults who are worried about having enough money for retirement is ( , ) (Use ascending order. Round to four decimal places as needed.)

Explanation / Answer

Sol:

sample proportion=p^=x/n

=succeesses/totlal

=650/1095

=0.5936073

sample szie=n=1095

z crit for 99%=2.576

99% confidence inetrval for population proportion is

sample prop-z crit sqrt(sample proportion(1-sampleproportion/(samplesize),sample prop+z crit sqrt(sample proportion(1-sampleproportion/t(samplesize)

0.5936-2.576sqrt(0.5936(1-0.5936/sqrt(1095),0.5936+2.576sqrt(0.5936(1-0.5936/sqrt(1095),

=0.5554,0.6318

0.5554<p<0.6318

We are 99% confident that

true proportion of adults who are worried about having enough money for retirement is

(0.5554,0.6318).

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