Free Class Schedule Maker ORX D RX E Web TV Service Provider Ana y D WeBWorK MU
ID: 3335970 • Letter: F
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Free Class Schedule Maker ORX D RX E Web TV Service Provider Ana y D WeBWorK MU STAT 1200 F × Free Class Schedule Maker × c Secure l https://webwork.math.missouri.edu/webwork2/MU-STAT-1200.FS17/WBwKS-fall/8/ Problam 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 0.03 At least one of the answers above is NOT correct (4 pts) In a carnival game, a player spins a wheel that stops with the pointer on one (and only one) of three colors. The likelihood of the pointer landing on each color is as follows: 63 percent BLUE, 20 percent RED, and 17 percent GREEN. Note: Your answers should be rounded to three decimal places. (a) Suppose we spin the wheel, observe the color that the pointer stops on, and repeat the process until the pointer stops on BLUE. What is the Display Options View equations as: MathJax probability that we will spin the wheel exactly three times? mages Show saved answers? Yes O No (b) Suppose we spin the wheel, observe the color that the pointer stops on, and repeat the process until the pointer stops on RED. What is the probability that we will spin the wheel at least three times? Apply Options (c) Suppose we spin the wheel, observe the color that the pointer stops on, and repeat the process until the pointer stops on GREEN. What is the probability that we will spin the wheel 2 or fewer times? Note: You can eam partial credit on this problem Preview Answers Submit Answers Your score was recorded. You have attempted this problem 1 time. You received a score of 0% for this attempt. Your overall recorded score is 0% You have unlimited attempts remaining.Explanation / Answer
a) Here we are given that P( Blue ) = 0.63
Probability that we spin the wheel exactly thrice here is computed as:
= (1 - P( Blue ) ) ( 1 - P( Blue ) ) * P( Blue )
= (1 - 0.63)2*0.63
= 0.086247
Therefore 0.086 is the required probability here.
b) P( red ) = 0.2
Probability that the wheel is spun at least 3 times is computed as:
= Probability that the first two spins are not red
= (1 - 0.2)2
= 0.64
Therefore 0.64 is the required probability here.
c) P( green ) = 0.17
Probability that we spin the wheel once or twice is computed as:
= P( green ) + (1 - P( green )) P( green )
= 0.17 + (1 - 0.17)*0.17
= 0.3111
Therefore 0.311 is the required probability here.
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