3. +-3 points MIntroStat6 7.E.072 My Notes Ask Your Te Assume X1 = 100, X2 = 121

Question

3. +-3 points MIntroStat6 7.E.072 My Notes Ask Your Te Assume X1 = 100, X2 = 121, s1 = 10, sz = 13, n1 = 50, and n2 = 50, Find a 95% confidence interval for the difference in the corresponding values of . (Round your answers to three decimal places.) Does this interval include more or fewer values than a 99% confidence interval? Explain your answer. This interval includes fewer values because a smaller confidence level means that we need a smaller margin of error O This interval includes fewer values because a smaller confidence level means that we need a larger margin of error. This interval includes more values because a smaller confidence level means that we need a smaller margin of error This interval includes more values because a smaller confidence level means that we need a larger margin of error

Explanation / Answer

Standard error, SE = sqrt [ s21 / n1 + s22 / n2 ] = 5.38

degree of freedom, df = (s12/n1 + s22/n2)2 / { [ (s12 / n1)2 / (n1 - 1) ] + [ (s22 / n2)2 / (n2 - 1) ] } = 91.95 = 92

tcrit = +/- 1.9864

95% CI = (121-100) +/- 1.9864*5.38 = (10.3132, 31.6868)

Answer : Option A.
This interval includes fewer values because a smaller confidence level means that we need a smaller margin of error

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.