Find a value of the standard normal random variable z, call it zo. such that the
ID: 3332412 • Letter: F
Question
Find a value of the standard normal random variable z, call it zo. such that the following probabilities are satisfied. e Home work a. P(ZSZo)0.0338 es & Test b, P(-zo szszo)=0.90 e. P(-Zo Szso)-0.3188 f. P-2 zo) 0.5 h, P(z zo) = 0.0026 cPl-zo5 z zo) = 0.99 dPl-zo s z s zo) = 0.8074 Plan zo-O (Round to two decimal places as needed.) Crunch pter Conten xt ls for Succes Enter your answer in the answer box and then click Check Answer. Clear All parts rchase Optioremaining pe here to search F12 F11Explanation / Answer
A) P(Z < z0) = 0.0338
Or, z0 = - 1.83
B) P(-z0 <Z < z0) = 0.9
Or, 2P(Z < z0) - 1 = 0.9
Or, P(Z < z0) = 0.95
Or, z0 = 1.65
C) P(-z0 < Z < z0) = 0.99
Or, 2P(Z < z0) - 1 = 0.99
Or, P(Z < z0) = 0.995
Or, z0 = 2.58
D) P(-z0 < Z < z0) = 0.8074
Or, P(Z < z0) = 0.9037
Or, z0 = 1.3
E) P(-z0 < Z < 0) = 0.3188
Or, P(Z < 0) - P(Z < - z0)= 0.3188
Or, 0.5 - P(Z < z0) = 0.3188
Or, P(Z < - z0) = 0.1812
Or, z0 = 0.91
F) P(-2 < Z < z0) = 0.9549
Or, P(Z < z0) - P(Z < - 2) = 0.9549
Or, P(Z < z0) - 0.0228 = 0.9549
Or, P(Z < z0) = 0.9777
Or, z0 = 2.01
G) P(Z > z0) = 0.5
Or, z0 = 0
H) P(Z < z0) = 0.0026
Or, z0 = - 2.8
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.