A concrete beam may fail either by shear (S) or flexure (F). Suppose that three

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A concrete beam may fail either by shear (S) or flexure (F). Suppose that three failed beams are randomly selected and the type of failure is determined for each one. Let X = the number of beams among the three selected that failed by shear. List each outcome in the sample space along with the associated value of X S: SFF FSF FFS FSS SFS SSF X: Need Help? Read It Talk to a Tutor 4/6 points | Previous Answers DevoreStat9 3.E.013 My Notes Ask Your Tei A mail-order company business has six telephone lines. Let X denote the number of lines in use at a specified time. Suppose the pmf of X is as given in the accompanying table p(x) 0.10 0.15 0.20 0.25 0.20 0.05 0.05 Calculate the probability of each of the following events. (e) between two and four lines, inclusive, are not in usej 35 (f) fat least four lines are not in usej .6 d Help? L Read It Oll Talk to a Tutor -4 points DevoreStat9 3E019 My Notes Ask Your Te A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday's mail. In actuality, each one may arrive on Wednesday, Thursday, Friday, Saturday. Suppose the two arrive independently of one another, and for each one P(wed.) = 0.28, P(Thurs.) = 0.37, P(Fr.) = 0.23, and p(Sat.) = 0.12. Let Y = the number of days beyor Wednesday that it takes for both magazines to arrive (so possible values are 0, 1, 2, or 3). Compute the pmf of Y. [Hint: There are 16 possible outcomes; YW,W)-0, YF,T)-2, anc so on.] (Enter your answers to four decimal places.) 0 P(Y) Need Help? Read ItTalk to a Tutor

Explanation / Answer

1)

2) Note: X is for lines in use
e) P(2 <= X <= 4) = 0.2+0.25+0.2 = 0.65
f) P(X <2) = 0.10+0.15 = 0.25

S FFF SFF FSF FFS FSS SFS SSF SSS X 0 1 1 1 2 2 2 3

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