(*explaining how to do this, step by step; while how to compute this with a TI-8
ID: 3330804 • Letter: #
Question
(*explaining how to do this, step by step; while how to compute this with a TI-84, if possible/ applicable please)
The owner of a local golf course wanted to determine the average age of the golfers that played on the course. In a random sample of 15 golfers that visited his course, the sample mean was 49.7 and the standard deviation was 7.388. Calculate a 95% confidence interval to estimate the average age of all golfers.
Question 1 options:
1)
(45.63596, 53.76404)
2)
(47.5552, 51.8448)
3)
(-45.6077, 53.7923)
4)
(47.792, 51.608)
5)
(45.6077, 53.7923)
1)
(45.63596, 53.76404)
2)
(47.5552, 51.8448)
3)
(-45.6077, 53.7923)
4)
(47.792, 51.608)
5)
(45.6077, 53.7923)
Explanation / Answer
n = 15
x-bar = 49.7
s = 7.388
% = 95
Standard Error, SE = s/n = 7.388/15 = 1.907573397
Degrees of freedom = n - 1 = 15 -1 = 14
t- score = 2.144786681
Width of the confidence interval = t * SE = 2.14478668128208 * 1.90757339745203 = 4.091338016
Lower Limit of the confidence interval = x-bar - width = 49.7 - 4.09133801642312 = 45.60866198
Upper Limit of the confidence interval = x-bar + width = 49.7 + 4.09133801642312 = 53.79133802
Answer: Option (5).
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