anong PSY212: Graded Assignment #3 Please note that This assignment includes com
ID: 3328897 • Letter: A
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anong PSY212: Graded Assignment #3 Please note that This assignment includes computations, each problem has several parts. For full redit, please respond to each part completely and shio tae-home q Please note that this assignment should be completed individually. Think of this assignment as plotting z-scores on a normal distribution and interpreting scores. Think of this assignment as a "take-home quiz. do not discuss this ass anyone other than your professor. Submit an electronic copy on Bb. 1. 1 sores have a meadadas viation of 15) John's IQ is 120, 3 points each a. What is the difference between John's IQ and the mean (in 1O poin enter text b. Convert John's IQ score to a z score. Click or tap here to enter text c. What percentage of scores fall between John's IQ and the mean IQ? Plot the distribution and evaluate. Click or tap here to enter text. d. Is John's IQ typical? Explain how you made your decision. Click or tap here toe e. What is the percentile rank of John's IQ? Click or tap here to enter text 2. Three students take different stress tests. 3 points each Sam: score o 144 on a test with a mean ef 128and a standard deviation a. Convert to a z-score Click or tap here to enter text b. Convert to a percentile Click or tap here to enter text c. Convert to a z-score Click or tap here to enter text. d. Convert to a percentile Click or tap here to enter text e. Convert to a z-score Click or tap here to enter text f. Convert to a percentile Click or tap here to enter text. Dillan: screof on a test with a mean of 89 and a standard deviation of 18 Will score o18 on a test with a mean of 15 and a standard.deyiation of 5 Of the three students who took a stress test, who had the highest relative score? Click or tap here to enter text. 3. Trey and Mike are both taking general psy this semester, but they are taking it with two ifferent professors. On their final exams, Trey got a 93 and Mike got an 88. In Trey's class, the mean score was an 85.0% (SD-4.00). In Mike's class, the mean score was 82 (SD-2.50). 3 points a) Compute a z-score for Trey. Click or tap here to enter text b) Compute a z-score for Mike. Click or tap here to enter text. person got the better exam grade, compared to the other people in their class? Click or tap here to enter text. what grade would Trey have needed to be in the top 10% of his class? Click or tap here to d) enter text e) Wha tgrade would Mike have needed to be in the top 10% of his class? Click or tap here to enter textExplanation / Answer
2)a) Z-score = (144 - 128)/ 34 = 0.47
B) P(Z < 0.47) = 0.6808 = 68.08 percentile
C) Z-score = (90 - 86)/18 = 0.22
D) P(Z < 0.22) =0.5871
E) Z-score = (18 - 15)/5 = 0.6
F) P(Z < 0.6) = 0.7257
3) a) Z-score = (93 - 85)/4 = 2
P(Z < 2) = 0.9772
B) Z-score = (88 - 82)/2.5 = 2.4
P(Z < 2.4) = 0.9918
C) Mike got the better grade.
D) P(X > x) = 0.1
Or, P((X - mean)/SD > (x - 85)/4) = 0.1
Or, P(Z > (x - 85)/4) = 0.1
Or, P(Z < (x - 85)/4) = 0.9
Or, (x - 85)/4 = 1.28
Or, x = 90.12
E) P(X > x) = 0.1
Or, P((x - mean)/SD > (x - 82)/2.5) = 0.1
Or, P(Z > (x - 82)/2.5) = 0.1
Or, P(Z < (x - 82)/2.5) = 0.9
Or, (x - 82)/2.5 = 1.28
Or, x = 85.2
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