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iPad 6:59 PM 34% . drive.google.com mens shoe store rome-Google Search isscm-fa17- mt1 exam.pdf-Google Drive 19. The average bear population in a park is 1,000 with a standard deviation of 200. What is the probability that the number of bears in a given year will be more than 1,300 bears? A. 86.6% B. 43.3% S6 20. What is the probability of a result greater than 3 on both of 2 roles of a 6 sided die? A. 2596 B. 5096 C. 100% 21. A couple plans to have 3 children. The probability of having at least 1 girl is: A. 13% B. 50% C. 88% 22. A family already has 4 girls. The probability that the 5th child is a boy is: A. 2% B. 2096 C. 5096 23. What is the probability of GBGBG in that order a family of 5 children. B. 31.3% C. 50.0% 24. What is probability of 3G and 2B in any order in family of 5 children. B. 31.3% C. 50.0%Explanation / Answer
19)
P(X > 1300) = P(z > (1300 - 1000)/200) = P(z > 1.5) = 0.0668
Hence 6.7% option (C)
20)
P(results greater than 3) = 3/6 = 1/2
Required probability = 1/2*1/2 = 1/4 = 0.25
hence 25% option (A)
21)
P(at least 1 girl = 1 - P(all boys) = 1 - (0.5)^3 = 0.875
Hence 88% option (C)
22)
As probability of having girl or boy is independent of the previous results, probability is always 0.5
hence 50%, option (C)
23)
required probability = (0.5)^5 = 0.03125
Hence 3.1%, option (A)
24)
required probability = 5C3*(0.5)^3*(0.5)^2 = 0.3125
hence 31.3% option (C)
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