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math l.com/Student/PlayerHomework aspchomeworkid-445489483&questionkaanushed; QMTH 205 Online Fall 17 Homework: Chapter 12 Homework Score: 0 of 1 pt 12.1.27 4016 (4 complete) HW Score: 6667 adol 6 A consumer organization estimates that over a 1-year period 15% of cars will need to be repaired once, 10% will need repairs twice, and 2% will require three or more repairs. What is the probability that a car chosen at random will need a) no repairs? b) no more than one repair? c) some repairs? . a) The pobability that a car will require no repairs is (Do not round.) b) The probability that a car will require no more than one repair is (Do no round) Enter your answer in the answer box and then click Check Answer chear All 238 PM 10/9/2017 ^4x

Explanation / Answer

1 repair = 15% = 0.15, 2 repairs = 10% = 0.1 and 3 repairs = 2% = 0.02

(a) Therefore probability of no repair = 1 - (0.15 + 0.1 + 0.02) = 0.73

(b) P(No More than 1 repair i.e at most 1 repair) = P(1 repair) + P(0 repairs) = 0.15 + 0.73 = 0.88

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