Will you answer these 4 questions please!! 1. In a previous study, an arborist h

Question

Will you answer these 4 questions please!!

1. In a previous study, an arborist has found that there were on average 12.1 spruce pines per acre, with a standard deviation of 3.49 in a particular section of forest. Use the appropriate model to calculate the approximate probability that exactly 10 spruce pines are found in the next randomly selected acre of this forest. a) 0.1031 b) 0.2743 c) 0.6017 d) 0.7257 e) 0.8969 2. Doct tors have developed a test for a disease which has specificity 0.85 (the probability It is negative when a patient does not have the disease is 0.85) and sensitivity 0.98 (when a patient does have the disease, the result is positive 98% of the time). Only 10% of patients tested for the disease at a particular clinic actually have it results come back positive, what is the probability that a patient at this clinic tested for the disease actually has it? . When the test a) 0.098 b) 0.128 c) 0.233 d) 0.421 e) 0.980 3. A baseball coach is looking at the types of pitches used by opposing teams' pitchers. What kind of graph is best for illustrating the data from the variable pitch type (fastball, curveball, slider, changeup, screwball)? a) box plot b) scatterplot c) dot plot d) histogram e) bar chart , The sampling distribution of sample proportion describes a) how the data distribtution looks like the population distribution when the sample size 4. is large. b) how the sample proportion gets closer to the population proportion by increasing the sample size. c) how individual observations tend to vary from one to another in a random sample. d) how sample proportions tend to vary from random sample to random sample. -e) how standard deviations tend to vary from random sample to random sample.

Explanation / Answer

Answer for 1 and 3 are below. Have handwritten for other questions. but I am getting an image upload error when uploading. Can you post the questions separately.

1.

We have modelled a normal distribution to solve the problem. Params have been given below:

Average = 12.1

Standard deviation = 3.49

We normalize using the params of the normal distribution given:

P(X=10)

= P(Z=10-12.1/3.49)

=P(Z=-0.6)

= .2743

3. e is right. It is the right chart to show categorical data. Here category is the type of pitch

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.