A survey found that women\'s heights are normally distributed with mean 635 in a

Question

A survey found that women's heights are normally distributed with mean 635 in and standard deviadion 25 in A branch of the military requires women's heights to be between 58 in and 80 in a. Find the percentage of b if this branch or the matary changes the height requirements so that all women are elgble except the shortest 1% and the tallest 2%, what are the new hei Click to yiewpage 1 of the table women m the height requirement Are many women being denied the opportunity to join this branch of the military because they are too short or too tall? t req"ements? a. The percentage of women who meet the height requirement is [ Round to two decimal places as needed) Are many women being denied the opportunity to join this branch of the military because they are too short or too tal? A. Yes, because the percentage of women who meet the height requirement is fairly large O B. No, because only a small percentage of women are not allowed to join this branch of the military because of their height ° C. Yes, because a large percentage of women are not allowed to join this branch of the military because of their height No, because the percentage of women who meet the height requirement is faily small b For the new height requirements, this branch of the mita y requires women's heights to be at least D. in and at most (Round to one decimal place as needed)

Explanation / Answer

Solution:

a) z value for 58 is (58-63.5/2.5=-5.5/2.5=-2.2

z value for 80 is (80-63.5)/2.5=16.5/2.5=6.6

The probability of z being between these is 0.9861

D. No, because only a small percentage of women are not allowed to join this branch of the military because of their height

b) invNorm(0.01) = -2.3265 ; invNorm(0.98) = 2.0538

Lower: x = -2.3265*2.5 + 63.5 =57.68
Upper: x = +2.0538*2.5 + 63.5 =68.63

For the new height requirements, this branch of the military requires women's heights to be at least given above in and at most given above in.

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