on the side of the graph the numbers are .00, .05, .10, .15, .20, . 25,.30. on t
ID: 3327187 • Letter: O
Question
on the side of the graph the numbers are .00, .05, .10, .15, .20, . 25,.30.
on top of the lines the numbers are line one .237 , line two .283, line three .165, line four .114, line five .094, line six .021, line seven.034, and line eight .052
(a) What is the probability that a randomly selected 44 to 49-year-old mother who had a live birth in 2015 has had her fourth live birth?
(b) What is the probability that a randomly selected 44- to 49-year-old mother who had a live birth in 2015 has had her fourth or fifth live birth?
(c) What is the probability that a randomly selected 44- to 49-year-old mother who had a live birth in 2015 has had her sixth or more live birth?
(d) If a 44- to 49-year-old mother who had a live birth in 2015 is randomly selected, how many live births would you expect the mother to have had?
years old who had a live birth in 2015. Complete parts (a) through (d) below that a randomly selected 44. to 49-year-old mother who had a live bith in 2015 has had her fourth or fith Sve birth? that a randomly selected 44- to 49-year-old mother who had a ive birth in 2015 has had her sixth or more ive birth? (Type an integer or a decimal) (d it a 44 to 49-year-old mother who had a live birth in 2015 is randomly selected how many Rive births would you expect the mother to have had?Explanation / Answer
a) Here, from the graph, we see that:
P(X = 4) = 0.114
Therefore 0.114 is the required probability here.
b) The required probability here is computed as:
P(X = 4) + P(X = 5) = 0.114 + 0.094 = 0.208
Therefore 0.208 is the required probability here.
c) Here the required probability is computed as:
P(X >= 6 ) = P(X = 6) + P(X = 7) + P(X = 8) = 0.021 + 0.034 + 0.052 = 0.107
Therefore 0.107 is the required probability here.
d) The expected value of X here is computed as:
E(X) = 1*P(X = 1) + 2P(X= 2) + ...... + 8P(X = 8)
E(X) = 1*0.237 + 2*0.283 + 3*0.165 + 4*0.114 + 5*0.094 + 6*0.021+ 7*0.034 + 8*0.052
E(X) = 3.004
Therefore 3.004 births would be expected the mother to have had.
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