Do Homework-Kristin Dor STAT-3001-5/STAT-3001L-S/STAT-3001P-5-Statistical Method

Question

Do Homework-Kristin Dor STAT-3001-5/STAT-3001L-S/STAT-3001P-5-Statistical Methods2017 Winter Qtr 11/27-02/18-PT3 Homework: Week 5 Assignment 1 Score: 0 of 9 pts 10.2.17 6016 (6 complete) Of the 94 paticpants in a drug trial who were given a now experimental treatment for arthnitis, 57 showed improvement Of the 90 participant mprovement Construct a two way table for these dala, and then use a 0.05 significance level to test the claim that improvement is independk given the drug or a placebo Complete the following two-way table no improvement 37 45 57 lacebo 45 a. State the null and the alternative hypotheses. Choose the correct answer below A. The null hypothesis Improvement is independent of whether the participant was given the drug or a placebo O B. The alternative hypothesis b. Assuming independence between the two variables, find the expected frequency for each cell of the table The aemative hypothesis: Improvement and treatment (drug or placebo) are somehow rellated The null hypothosis Improvement and treatment (drug or placebo) are somehow relstod Table of expected frequencies Drug Placebo (Round to the nearest hundredth as needed) Enter your answer in the edit fields and then click Check Answer Cloar All

Explanation / Answer

Answer:

Based on the given information:

Drug group:

Control group:

Complete the following two-way table:

State the Null and Alternative Hypothesis:

A) is the correct option

Null Hypothesis: Improvement is independent of whether the participant was given the drug or a placebo

Alternate Hypothesis: Improvement and treatment (drug or placebo) are somehow related.

b. Assuming independence between the two variables, find the expected frequency for each cell of the table.

If the two variables are independent, then it is expected to have equal number of participants belonging to each group.

This is an example of case-control study. The expected frequencies in different cell can be determined as below:

Cell (1,1) Expected frequency = (102*94)/184 = 52.11

Cell (1,2) Expected frequency = (82*94)/184 = 41.89

Cell (2,1) Expected frequency = (102*90)/184 = 49.89

Cell (2,2) Expected frequency = (82*90)/184 = 40.11

Therefore, table of expected frequencies is:

Improvement No Improvement Total Drug 57 37 94 Placebo 45 45 90 Total 102 82 184

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